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C语言实现五子棋小游戏

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C语言实现五子棋小游戏

首先我们先来看一个稍微简单些的实现方式:

#include 
#include 

#define N 15

int chessboard[N + 1][N + 1] = { 0 };

int whoseTurn = 0;

void initGame(void);
void printChessboard(void);
void playChess(void);
int judge(int, int);

int main(void)
{
 initGame();

 while (1)
 {
  whoseTurn++;

  playChess();
 }

 return 0;
}

void initGame(void)
{
 char c;

 printf("Please input 'y' to enter the game:");
 c = getchar();
 if ('y' != c && 'Y' != c)
  exit(0);

 system("cls");
 printChessboard();
}

void printChessboard(void)
{
 int i, j;

 for (i = 0; i <= N; i++)
 {
  for (j = 0; j <= N; j++)
  {
   if (0 == i)
    printf("%3d", j);
   else if (j == 0)
    printf("%3d", i);
   else if (1 == chessboard[i][j])
    printf(" O");
   else if (2 == chessboard[i][j])
    printf(" X");
   else
    printf(" *");
  }
  printf("n");
 }
}

void playChess(void)
{
 int i, j, winner;

 if (1 == whoseTurn % 2)
 {
  printf("Turn to player 1, please input the position:");
  scanf("%d %d", &i, &j);

  while (chessboard[i][j] != 0)
  {
   printf("This position has been occupied, please input the position again:");
   scanf("%d %d", &i, &j);
  }

  chessboard[i][j] = 1;
 }
 else
 {
  printf("Turn to player 1, please input the position:");
  scanf("%d %d", &i, &j);

  while (chessboard[i][j] != 0)
  {
   printf("This position has been occupied, please input the position again:");
   scanf("%d %d", &i, &j);
  }

  chessboard[i][j] = 2;
 }

 system("cls");
 printChessboard();

 if (judge(i, j))
 {
  if (1 == whoseTurn % 2)
  {
   printf("Winner is player 1!n");
   exit(0);
  }
  else
  {
   printf("Winner is player 2!n");
   exit(0);
  }
 }
}

int judge(int x, int y)
{
 int i, j;
 int t = 2 - whoseTurn % 2;

 for (i = x - 4, j = y; i <= x; i++)
 {
  if (i >= 1 && i <= N - 4 && t == chessboard[i][j] && t == chessboard[i + 1][j] && t == chessboard[i + 2][j] && t == chessboard[i + 3][j] && t == chessboard[i + 4][j])
   return 1;
 }
 for (i = x, j = y - 4; j <= y; j++)
 {
  if (j >= 1 && j <= N - 4 && t == chessboard[i][j] && t == chessboard[i][j + 1] && t == chessboard[i][j + 1] && t == chessboard[i][j + 3] && t == chessboard[i][j + 4])
   return 1;
 }
 for (i = x - 4, j = y - 4; i <= x, j <= y; i++, j++)
 {
  if (i >= 1 && i <= N - 4 && j >= 1 && j <= N - 4 && t == chessboard[i][j] && t == chessboard[i + 1][j + 1] && t == chessboard[i + 2][j + 2] && t == chessboard[i + 3][j + 3] && t == chessboard[i + 4][j + 4])
   return 1;
 }
 for (i = x + 4, j = y - 4; i >= 1, j <= y; i--, j++)
 {
  if (i >= 1 && i <= N - 4 && j >= 1 && j <= N - 4 && t == chessboard[i][j] && t == chessboard[i - 1][j + 1] && t == chessboard[i - 2][j + 2] && t == chessboard[i - 3][j + 3] && t == chessboard[i - 4][j + 4])
   return 1;
 }

 return 0;
}

演示截图

我们再来看一个更复杂些的

C语言实现五子棋小游戏

# include
# include
# include
# include//插入输入输出头文件
# include//字符数组的函数定义的头文件
# include//stdlib 头文件即standard library标准库头文件stdlib 头文件里包含了C、C++语言的最常用的系统函数该 ,文件包含了C语言标准库函数的定义.
# define SPA 0//在C或C++语言源程序中允许用一个标识符来表示一个字符串,称为“宏”。 “define”为宏定义命令。
# define MAN 1
# define COM 2
 
#define ORDEX 15
int qipan[ORDEX][ORDEX]; //自己定义的预处理函数,以二维数组形式构建棋盘 

typedef struct//typedef的作用是在C中定义一个结构体类型
{
 int iFlag;
 int iX, iY;
}ScmPiece;
int g_iPieceLen;
ScmPiece g_ScmGame1, g_ScmGame2;

void start(); 
void draw(); 
int Victory( ScmPiece * pScmPiece ); 
void AI(int *p,int *q);  
int value(int p,int q);  
int qixing(int n,int p,int q); 
void yiwei(int n,int *i,int *j); 

void InitGame(){
 int i;
 g_iPieceLen = ORDEX * ORDEX;
 g_ScmGame1.iX = 0;
 g_ScmGame1.iY = 0;
 g_ScmGame1.iFlag = COM;
 g_ScmGame2.iX = 7;
 g_ScmGame2.iY = 7;
 g_ScmGame2.iFlag = MAN;
 for( i=0; i < ORDEX*ORDEX; ++i )
  *( (int*)qipan + i ) = SPA;
}

void main()
{
 char k;
 do{
  InitGame();
  start();
  printf("还要再来一把吗?输入y或n:"); getchar(); scanf("%c",&k);
  while(k!='y'&&k!='n'){ printf("输入错误,请重新输入n"); scanf("%c",&k); }
  system("cls");
 }while(k=='y');
 printf("谢谢使用!n");
}
void MakePiece( ScmPiece * pScmPiece, int iGameFlag ){
 if( iGameFlag )
 {
  printf("请下子:");
  while( scanf( "%d%d", &pScmPiece->iX, &pScmPiece->iY ) )
  {
   if( ( pScmPiece->iX < 0 || pScmPiece->iX > ORDEX-1 ) || ( pScmPiece->iY < 0 || pScmPiece->iY > ORDEX-1 ) )
    printf( "坐标错误!请重新输入:");
   else if( qipan[pScmPiece->iX][pScmPiece->iY] )
    printf( "该位置已有子!请重新输入:");
   else break;
  }
 }
 qipan[pScmPiece->iX][pScmPiece->iY] = pScmPiece->iFlag;
 --g_iPieceLen;
 system("cls");
 draw();
 if( iGameFlag == 0 )
  printf("电脑下在%d %dn", pScmPiece->iX, pScmPiece->iY );
}
void start()
{
 int choice;
 //ScmPiece ScmGameTemp1, ScmGameTemp2;
 printf("t╔═══════════════════════════════╗n");
 printf("t║  ║n");
 printf("t║  欢迎使用五子棋对战程序  祝您玩的愉快挑战无极限  ║n");
 printf("t║  ║n");
 printf("t║     ._______________________.     ║n"); 
 printf("t║     | _____________________ |     ║n");
 printf("t║     | I     I |     ║n");
 printf("t║     | I     I |     ║n");
 printf("t║     | I  五 子 棋  I |     ║n");
 printf("t║     | I     I |     ║n");
  printf("t║     | I___________________I |     ║n");
 printf("t║     !_______________________!     ║n");
  printf("t║      ._[__________]_.║n");
 printf("t║     .___|_______________|___.     ║n");
 printf("t║     |::: ____    |      ║n"); 
 printf("t║     | ~~~~ [CD-ROM] |      ║n");
 printf("t║     !_____________________!      ║n");
 printf("t║  ║n");
 printf("t║  ║n");
 printf("t║   寒 星 溪 月 疏 星 首,花 残 二 月 并 白 莲。   ║n");
 printf("t║   雨 月 金 星 追 黑 玉,松 丘 新 宵 瑞 山 腥。   ║n");
 printf("t║   星 月 长 峡 恒 水 流,白 莲 垂 俏 云 浦 岚。   ║n");
 printf("t║   黑 玉 银 月 倚 明 星,斜 月 明 月 堪 称 朋。   ║n");
 printf("t║   二 十 六 局 先 弃 二,直 指 游 星 斜 彗 星。   ║n");
 printf("t║  ║n");
 printf("t║  ║n");
 printf("t║   1.人机对战     2.人人对战    ║n");
 printf("t║  ║n");
 printf("t╚═══════════════════════════════╝n");
 printf("ttt请输入1或2:");
 while( scanf( "%d", &choice ), choice!=1 && choice!=2 )
  printf( "输入错误,请重新输入:" );
 system("cls"); 
 if( choice == 1 )
 {  
  printf("ttt欢迎使用五子棋人机对战!ntt下子请输入坐标(如13 6)中间以空格分隔。nnn"); 
  draw();
  printf("先下请按1,后下请按2:");
  while( scanf( "%d", &choice ), choice!=1 && choice!=2 )
   printf( "输入错 误,请重新输入:" );
  if( choice == 2 )
   MakePiece( &g_ScmGame2, 0 );
  choice = 1;
 }
 else
 {
  printf("欢迎使用五子棋人人对战!下子请输入坐标(如13 6)。悔棋请输入15 15。 nnn"); 
  draw();
 }
 while( g_iPieceLen )
 {
  MakePiece( &g_ScmGame1, 1 );
  if( Victory( &g_ScmGame1 ) )
  {
   printf("电脑神马的都是浮云!!!n");
   return;
  } 
  if( choice == 1 )
  {
   AI( &g_ScmGame2.iY, &g_ScmGame2.iX );
   MakePiece( &g_ScmGame2, 0 );
   if( Victory( &g_ScmGame2 ) )
   {    
    int iChoice;
    printf("要悔棋吗?请输入y或n:");
STARTFLAGE:
    setbuf( stdin, NULL );
    scanf( "%c", &iChoice );
    switch( (char)iChoice ){
    case 'y':
    case 'Y':
     g_iPieceLen += 2;
     qipan[g_ScmGame2.iX][g_ScmGame2.iY] = SPA;
     qipan[g_ScmGame1.iX][g_ScmGame1.iY] = SPA;
     system("cls"); draw();
     break;
    case 'n':
    case 'N':
     printf( "下不过电脑很正常,请不要灰心!!!n" );
     return;
    default:
     printf("输入错误,请重新输入:");
     goto STARTFLAGE;
    }
   }
  }
  else
  {
   MakePiece( &g_ScmGame2, 1 );
   if( Victory( &g_ScmGame2 ) )
   {
    printf("电脑神马的都是浮云!!!n");
    return;
   }
  }
 }
 printf("和局n");
}
void draw() 
{
 int i,j;
 char p[15][15][4];
 for(j=0;j<15;j++)
  for(i=0;i<15;i++){
   if(qipan[j][i]==SPA) strcpy(p[j][i]," ");
   if(qipan[j][i]==MAN) strcpy(p[j][i],"●");
   if(qipan[j][i]==COM) strcpy(p[j][i],"◎");
  }
 printf("   0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 n"); 
 printf("  ┌─┬─┬─┬─┬─┬─┬─┬─┬─┬─┬─┬─┬─┬─┬─┐n");
 for(i=0,j=0;i<14;i++,j++){
 printf("  %2d│%s│%s│%s│%s│%s│%s│%s│%s│%s│%s│%s│%s│%s│%s│%s│%dn",j,p[i][0],p[i][1],p[i][2],p[i][3],p[i][4],p[i][5],p[i][6],p[i][7],p[i][8],p[i][9],p[i][10],p[i][11],p[i][12],p[i][13],p[i][14],j);
 printf("  ├─┼─┼─┼─┼─┼─┼─┼─┼─┼─┼─┼─┼─┼─┼─┤n");
 }
 printf("  14│%s│%s│%s│%s│%s│%s│%s│%s│%s│%s│%s│%s│%s│%s│%s│0n",p[14][0],p[14][1],p[14][2],p[14][3],p[14][4],p[14][5],p[14][6],p[14][7],p[14][8],p[14][9],p[14][10],p[14][11],p[14][12],p[14][13],p[14][14]);
 printf("  └─┴─┴─┴─┴─┴─┴─┴─┴─┴─┴─┴─┴─┴─┴─┘n");
 printf("   0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 n");
}
static int DirectionValue( int * piX, int * piY, int iDirection ){
 switch( iDirection ){
 case 0:
  --*piX;
  break;
 case 4:
  ++*piX;
  break;
 case 1:
  --*piY;
  break;
 case 5:
  ++*piY;
  break;
 case 2:
  --*piX; --*piY;
  break;
 case 6:
  ++*piX; ++*piY;
  break;
 case 3:
  --*piX; ++*piY;
  break;
 case 7:
   ++*piX; --*piY;
  break;
 }
 if( (*piX >= 0 && *piX <= ORDEX-1) && (*piY >= 0 && *piY <= ORDEX-1) )
  return 1;
 else return 0;
}
static int SubVictory( ScmPiece * pScmPiece, int iDirection ){
 int iX = pScmPiece->iX;
 int iY = pScmPiece->iY;
 int iPieceCount = 1;
 while( DirectionValue( &iX, &iY, iDirection ) && qipan[iX][iY] == pScmPiece->iFlag )
  ++iPieceCount;
 iX = pScmPiece->iX;
 iY = pScmPiece->iY;
 while( DirectionValue( &iX, &iY, iDirection+4 ) && qipan[iX][iY] == pScmPiece->iFlag )
  ++iPieceCount;
 return iPieceCount;
}
int Victory( ScmPiece * pScmPiece )  
{
 int iDirection = 0;
 while( iDirection < 4 )
  if( SubVictory( pScmPiece, iDirection++ ) >= 5 )
   return 1;
 return 0;
}
void AI(int *p,int *q)   
{
 int i,j,k,max=0,I,J;  
 for(j=0;j<15;j++)
  for(i=0;i<15;i++)
   if(qipan[j][i]==SPA){  
    k=value(i,j);
    if(k>=max) { I=i; J=j; max=k; }
   }
 *p=I; *q=J;
}
int value(int p,int q)  
{
 int n=1,k=0,k1,k2,K1,K2,X1,Y1,Z1,X2,Y2,Z2,temp; 
 int a[2][4][4]={40,400,3000,10000,6,10,600,10000,20,120,200,0,6,10,500,0,30,300,2500,5000,2,8,300,8000,26,160,0,0,4,20,300,0};
   
 while(n!=5){
  k1=qixing(n,p,q); n+=4;   
  k2=qixing(n,p,q); n-=3;
  if(k1>k2) { temp=k1; k1=k2; k2=temp; } 
  K1=k1; K2=k2;  
  Z1=k1%10; Z2=k2%10; k1/=10; k2/=10; Y1=k1%10; Y2=k2%10; k1/=10; k2/=10; X1=k1%10; X2=k2%10;
   
  if(K1==-1) { if(K2<0) { k+=0; continue; } else k+=a[X2][Y2][Z2]+5; continue; }; 
  if(K1==-2) { if(K2<0) { k+=0; continue; } else k+=a[X2][Y2][Z2]/2; continue; };   
  if(K1==-3) { if(K2<0) { k+=0; continue; } else k+=a[X2][Y2][Z2]/3; continue; };  
  if(((K1>-1&&K1<4)&&((K2>-1&&K2<4)||(K2>9&&K2<14)))||((K1>99&&K1<104)&&((K2>99&&K2<104)||(K2>109&&K2<114)))){
   
   if(Z1+Z2>=2) { k+=a[X2][Y2][3]; continue; }
   else { k+=a[X2][Y2][Z1+Z2+1]; continue; }
  }
  if(((K1>9&&K1<14)&&(K2>9&&K2<14))||((K1>109&&K1<114)&&(K2>109&&K2<114))){
   
   if(Z1+Z2>=2) { k+=10000; continue; }
   else { k+=0; continue; }
  }
  if(((K1>-1&&K1<4)&&((K2>99&&K2<104)||(K2>109&&K2<114)))||((K1>9&&K1<14)&&((K2>99&&K2<104)||(K2>109&&K2<1 14)))){
   
   if(Z1==3||Z2==3) { k+=10000; continue; }
   else { k+=a[X2][Y2][Z2]+a[X1][Y1][Z1]/4; continue; } 
  }
  else { k+=a[X1][Y1][Z1]+a[X2][Y2][Z2]; continue; } 
 }
 return k;
}
int qixing(int n,int p,int q)    
{
 int k,m=0; 
 yiwei(n,&p,&q);
 if(p<0||p>14||q<0||q>14) k=-2;   
 switch(qipan[q][p]){
  case COM:{
     m++; yiwei(n,&p,&q);
     if(p<0||p>14||q<0||q>14) { k=m+9; return k; }
     while(qipan[q][p]==COM) { m++; yiwei(n,&p,&q); if(p<0||p>14||q<0||q>14) { k=m+9; return k; } }
     if(qipan[q][p]==SPA) k=m-1;
      else k=m+9;    
     }break;
  case MAN:{
     m++; yiwei(n,&p,&q);
     if(p<0||p>14||q<0||q>14) { k=m+109; return k; }
     while(qipan[q][p]==MAN) { m++; yiwei(n,&p,&q); if(p<0||p>14||q<0||q>14) { k=m+109; return k; } }
     if(qipan[q][p]==SPA) k=m+99;
     else k=m+109;   
     }break;
  case SPA:{
     yiwei(n,&p,&q);
     if(p<0||p>14||q<0||q>14) { k=-3; return k; }   
     switch(qipan[q][p]){
     case COM:{
 m++; yiwei(n,&p,&q);
 if(p<0||p>14||q<0||q>14) { k=m+29; return k; }
 while(qipan[q][p]==COM) { m++; yiwei(n,&p,&q); if(p<0||p>14||q<0||q>14) { k=m+29; return k; } }
 if(qipan[q][p]==SPA) k=m+19;      
 else k=m+29;   
 }break;
     case MAN:{
 m++; yiwei(n,&p,&q);
 if(p<0||p>14||q<0||q>14) { k=m+129; return k; }
 while(qipan[q][p]==MAN) { m++; yiwei(n,&p,&q); if(p<0||p>14||q<0||q>14) { k=m+129; return k; } }   
 if(qipan[q][p]==SPA) k=m+119;      
 else k=m+129;    
 }break;
     case SPA: k=-1; break;    
     }
    }break;
 }
 return k;
}
void yiwei(int n,int *i,int *j)  
{
 switch(n){
 case 1: *i+=1; break;
 case 2: *i+=1; *j+=1; break;
 case 3: *j+=1; break;
 case 4: *i-=1; *j+=1; break;
 case 5: *i-=1; break;
 case 6: *i-=1; *j-=1; break;
 case 7: *j-=1; break;
 case 8: *i+=1; *j-=1; break;
 }
}

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