冒泡排序
1.原理:比较两个相邻的元素,将值大的元素交换到右边
N个数字要排序完成,总共进行N-1趟排序,每i趟的排序次数为(N-i)次,所以可以用双重循环语句,外层控制循环多少趟,内层控制每一趟的循环次数
int[] arr = {3,5,1,4,2};
for (int i = 0; i arr[j+1]){
int temp = arr[j];
arr[j] = arr[j+1];
arr[j+1] = temp;
}
}
}
for (int i = 0; i < arr.length; i++) {
System.out.print(arr[i]+" ");
}
打印菱形
public static void main(String[] args) {
System.out.println("请输入菱形行数");
Scanner sc = new Scanner(System.in);
System.out.print("输入行数:");
int num = sc.nextInt();
for (int i = 0; i i+1; j--) {
System.out.print(" ");
}
for (int k = 0; k <= 2*i-1; k++) {
System.out.print("*");
}
System.out.println("*");
}
for (int i = 1; i < num; i++) {
for (int j = 0; j < i; j++) {
System.out.print(" ");
}
for (int k = 0; k < 2*(num-i)-1 ; k++) {
System.out.print("*");
}
System.out.println();
}
}



