您可以使用
itertools.chain.from_iterable：
>>> from itertools import chain>>> example_list = [['aaa'], ['fff', 'gg'], ['ff'], ['', 'gg']]>>> '' in chain.from_iterable(example_list)True
万一如果内部列表更大（超过100个项目），则
any与生成器一起使用的速度将比上面的示例更快，因为这样，使用Python
for循环的速度代价将由快速
in操作来补偿：
>>> any('' in x for x in example_list)True时序比较：
>>> example_list = [['aaa']*1000, ['fff', 'gg']*1000, ['gg']*1000]*10000 + [['']*1000]>>> %timeit '' in chain.from_iterable(example_list)1 loops, best of 3: 706 ms per loop>>> %timeit any('' in x for x in example_list)1 loops, best of 3: 417 ms per loop# With smaller inner lists for-loop makes `any()` version little slow>>> example_list = [['aaa'], ['fff', 'gg'], ['gg', 'kk']]*10000 + [['']]>>> %timeit '' in chain.from_iterable(example_list)100 loops, best of 3: 2 ms per loop>>> %timeit any('' in x for x in example_list)100 loops, best of 3: 2.65 ms per loop
