没有用于
timedelta对象的内置格式化程序，但是您自己可以很容易地做到这一点：
days, seconds = duration.days, duration.secondshours = days * 24 + seconds // 3600minutes = (seconds % 3600) // 60seconds = seconds % 60
或者，等效地，如果您使用的是Python 2.7+或3.2+：
seconds = duration.total_seconds()hours = seconds // 3600minutes = (seconds % 3600) // 60seconds = seconds % 60
现在，您可以根据需要打印它：
'{} minutes, {} hours'.format(minutes, hours)例如：
def convert_timedelta(duration): days, seconds = duration.days, duration.seconds hours = days * 24 + seconds // 3600 minutes = (seconds % 3600) // 60 seconds = (seconds % 60) return hours, minutes, secondstd = datetime.timedelta(2, 7743, 12345)hours, minutes, seconds = convert_timedelta(td)print '{} minutes, {} hours'.format(minutes, hours)这将打印：
9 minutes, 50 hours
如果要获取“ 10分钟1小时”而不是“ 10分钟1小时”，则也需要手动执行此操作：
print '{} minute{}, {} hour{}'.format(minutes, 's' if minutes != 1 else '', hours, 's' if minutes != 1 else '')或者，您可能想编写一个
english_plural函数
's'为您完成这些操作，而不是重复自己。
从您的评论看来，您实际上是想让日子分开。这更容易：
def convert_timedelta(duration): days, seconds = duration.days, duration.seconds hours = seconds // 3600 minutes = (seconds % 3600) // 60 seconds = (seconds % 60) return days, hours, minutes, seconds
如果要将其转换为单个值以存储在数据库中，然后将该单个值转换回以对其进行格式化，请执行以下操作：
def dhms_to_seconds(days, hours, minutes, seconds): return (((days * 24) + hours) * 60 + minutes) * 60 + secondsdef seconds_to_dhms(seconds): days = seconds // (3600 * 24) hours = (seconds // 3600) % 24 minutes = (seconds // 60) % 60 seconds = seconds % 60 return days, hours, minutes, seconds
因此，将其放在一起：
def store_timedelta_in_database(thingy, duration): seconds = dhms_to_seconds(*convert_timedelta(duration)) db.execute('INSERT INTO foo (thingy, duration) VALUES (?, ?)', thingy, seconds) db.commit()def print_timedelta_from_database(thingy): cur = db.execute('SELECt duration FROM foo WHERe thingy = ?', thingy) seconds = int(cur.fetchone()[0]) days, hours, minutes, seconds = seconds_to_dhms(seconds) print '{} took {} minutes, {} hours, {} days'.format(thingy, minutes, hours, days)
