下面是困难的方法。这是简单的方法。不知道为什么我早就没想到。
import inspectdef get_user_attributes(cls): boring = dir(type('dummy', (object,), {})) return [item for item in inspect.getmembers(cls) if item[0] not in boring]这是一个开始
def get_user_attributes(cls): boring = dir(type('dummy', (object,), {})) attrs = {} bases = reversed(inspect.getmro(cls)) for base in bases: if hasattr(base, '__dict__'): attrs.update(base.__dict__) elif hasattr(base, '__slots__'): if hasattr(base, base.__slots__[0]): # We're dealing with a non-string sequence or one char string for item in base.__slots__: attrs[item] = getattr(base, item) else: # We're dealing with a single identifier as a string attrs[base.__slots__] = getattr(base, base.__slots__) for key in boring: del attrs['key'] # we can be sure it will be present so no need to guard this return attrs这应该相当健壮。本质上，它通过获取
object要忽略的默认子类上的属性来工作。然后，它获取传递给它的类的mro并以相反的顺序遍历它，以便子类键可以覆盖超类键。它返回键值对的字典。如果您想要一个键列表，
inspect.getmembers则使用in中的值元组，然后在Python
3中返回
attrs.items()或
list(attrs.items())。
如果您实际上并不想遍历mro，而只想直接在子类上定义属性，那么它会更容易：
def get_user_attributes(cls): boring = dir(type('dummy', (object,), {})) if hasattr(cls, '__dict__'): attrs = cls.__dict__.copy() elif hasattr(cls, '__slots__'): if hasattr(base, base.__slots__[0]): # We're dealing with a non-string sequence or one char string for item in base.__slots__: attrs[item] = getattr(base, item) else: # We're dealing with a single identifier as a string attrs[base.__slots__] = getattr(base, base.__slots__) for key in boring: del attrs['key'] # we can be sure it will be present so no need to guard this return attrs
