我可能不明白您所描述的一切。通过阅读您的问题和其他人的评论，我想这就是您要寻找的：
更新后的版本：
with cteOriginal as( select *, RANK() over (partition by [SortOrder] order by id asc) as [NonUniqueSortOrder] from ( select id, A as [value], 1 as [SortOrder] from #original where A is not null union all select id, B as [value], 2 as [SortOrder] from #original where B is not null union all select id, C as [value], 3 as [SortOrder] from #original where C is not null union all select id, D as [value], 4 as [SortOrder] from #original where D is not null ) as temp)select [value]from cteOriginalwhere id = (select MIN(tmp.id) from cteOriginal tmp where tmp.value = cteOriginal.value)order by ((([NonUniqueSortOrder] - 1) * 4) + [SortOrder])
我通过选择具有最小id（min（id））的重复值来摆脱重复值。您可以将其更改为使用max（id）。
初始版本：
with cteOriginal as( select *, RANK() over (partition by [column] order by id asc) as [NonUniqueSortOrder] from ( select id, A as [value], 'A' as [Column], 1 as [SortOrder] from #original where A is not null union all select id, B as [value], 'B' as [Column], 2 as [SortOrder] from #original where B is not null union all select id, C as [value], 'C' as [Column], 3 as [SortOrder] from #original where C is not null union all select id, D as [value], 'D' as [Column], 4 as [SortOrder] from #original where D is not null ) as temp)select [value]from cteOriginalorder by ((([NonUniqueSortOrder] - 1) * 4) + [SortOrder])
顺便说一句，我正在使用mssql 2005进行此查询。请发表评论，我们将对其进行完善。
