编辑： 亚当·里特瑙尔的答案可能是现在最好的答案。要对此进行扩展，您可以查看iOS
8.3核心音频更改中的新实用程序功能/类型。
UnsafeMutableAudioBufferListPointer可用于读取/访问某些给定数据：
struct UnsafeMutableAudioBufferListPointer { init(_ p: UnsafeMutablePointer<AudioBufferList>) var count: Int subscript (index: Int) -> AudioBuffer { get nonmutating set }}您可以使用AudioBuffer和AudioBufferList上的扩展来分配自己的扩展名：
extension AudioBufferList { static func sizeInBytes(maximumBuffers maximumBuffers: Int) -> Int static func allocate(maximumBuffers maximumBuffers: Int) -> UnsafeMutableAudioBufferListPointer}extension AudioBuffer { init<Element>(_ typedBuffer: UnsafeMutableBufferPointer<Element>, numberOfChannels: Int)}旧答案：
这有点棘手，因为
AudioBufferList它实际上是一个可变大小的结构。这意味着它被声明为具有single
AudioBuffer，但实际上它具有
mNumberBuffers成员指定的数量。这个概念不能很好地转化为Swift，这就是为什么您看到了
varmBuffers: (AudioBuffer)。
因此，访问这些缓冲区及其数据的规范方法是使用
UnsafeArray。下面的代码提供了一些想法，但是
UnsafePointer并
UnsafeArray没有得到很好的记录，因此这可能是错误的。
// ***WARNING: UNTESTED CODE AHEAD***let foo: UnsafePointer<AudioBufferList> // from elsewhere...// This looks intuitive, but accessing `foo.memory` may be doing a copy.let bufs = UnsafeArray<AudioBuffer>(start: &foo.memory.mBuffers, length: Int(foo.memory.mNumberBuffers))// This is another alternative that should work...let bufsStart = UnsafePointer<AudioBuffer>(UnsafePointer<UInt32>(foo) + 1) // Offset to mBuffers memberlet bufs = UnsafeArray<AudioBuffer>(start: bufsStart, length: Int(foo.memory.mNumberBuffers))// Hopefully this isn't doing a copy, but it shouldn't be too much of a problem anyway.let buf: AudioBuffer = bufs[0] // or you could use a for loop over bufs, etc.typealias MySample = Float32let numSamples = Int(buf.mDataByteSize / UInt32(sizeof(MySample)))let samples = UnsafeArray<MySample>(start: UnsafePointer<MySample>(buf.mData), length: numSamples)// Now use the samples array...
这似乎在操场上可行，但对我来说很难测试真实的音频数据。特别是，我不确定100％
start:&foo.memory.mBuffers会按预期使用。（尽管数据似乎存在，但它返回的指针与原始指针不同。）试一下并报告！
编辑：顺便调试一下，您可以例如：
(lldb) p foo(UnsafePointer<AudioBufferList>) $R1 = (value = Builtin.RawPointer = 0x0000000100700740)(lldb) expr -lc -- ((int*)0x0000000100700740)[0](int) $2 = 42(lldb) expr -lc -- ((int*)0x0000000100700740)[1](int) $3 = 43...
