如何使用Struts2和Hibernate维护会话？

您应该将按钮映射到实际使用的方法。缺省操作映射器允许使用按钮名称或

method

<s:form action="person">    <s:textfield label="Enter your name" name="person.name"/>    <s:submit value="Add person" method="add"/>    <s:submit value="Create persons"/></s:form>

现在，在您执行的操作中

SessionAware

public class PersonAction extends ActionSupport implements SessionAware {  private Person person = new Person();  public Person getPerson() {    return person;  }  public setPerson(Person person){    this.person = person;  }  private Map<String, Object> session;  public setSession(Map<String, Object> session){    this.session = session;  }  public String execute() { //Create persons    List<Person> personList = (List<Person>) session.get("personList");    for (Person p : personList)     getPersonService().save(p); // save to db    //clear the list    personList.clear();    return SUCCESS;  }  public String add() { //Add person    List<Person> personList = (List<Person>) session.get("personList");    if (personList == null) {      personList = new ArrayList<Person>();      session.put("personList", personList);    }    personList.add(person);    return SUCCESS;  }}

现在，您已经通过映射到相应按钮的方法分离了逻辑。为了确保工作正常，请确保已打开DMI（动态方法调用）（默认情况下处于打开状态），并且将拦截器堆栈

defaultStack

struts.xml：

<?xml version="1.0" encoding="UTF-8" ?><!DOCTYPE struts PUBLIC  "-//Apache Software Foundation//DTD Struts Configuration 2.3//EN"  "http://struts.apache.org/dtds/struts-2.3.dtd"><struts>  <constant name="struts.devMode" value="false"/>  <package name="default" extends="struts-default">    <action name="person" >      <result>/person.jsp</result>    </action>  </package></struts>

SessionAware

ActionContext