如何从另一个表中获得具有匹配ID的另一个表中的名称？

它的内容并不能完全回答问题，但是会建议您如何正确规范化表以简化问题。

这是一种

Many-to-Many

Employees- ID (Primary Key)- Name- TypeTask- ID (Primary Key)- NameWork- EmployeeID (Foreign Key)- TaskID (Foreign Key)

员工表

id         name        type 1         john         2 2         peter        1 3         leah         2 4         frank        1 5         tang         3

任务表

 id         name          1         task1         2         task2         3         task3         4         task4

工作表

TaskID  EmployeeID1113222431323344

询问，

SELECt  t.ID, t.Name,        STUFF(        (SELECT ',' + b.Name        FROM    Work a     INNER JOIN Employee b         ON a.EmployeeID = b.ID        WHERe   a.TaskID = t.ID         FOR XML PATH (''))        , 1, 1, '')  AS NamesListFROM    Task t-- WHERe    ..... -- add additional conditions...GROUP   BY t.ID, t.Name

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