您可以
scipy.interpolate像在这个问题中看到的那样使用B样条曲线插值。
在这里，我将使用 B样条 示例之一来获取
x和的值
y：
import numpy as npimport scipy.interpolate as si# Curve base:points = [[0, 0], [0, 2], [2, 3], [4, 0], [6, 3], [8, 2], [8, 0]];points = np.array(points)x = points[:,0]y = points[:,1]t = range(len(points))ipl_t = np.linspace(0.0, len(points) - 1, 100)x_tup = si.splrep(t, x, k=3)y_tup = si.splrep(t, y, k=3)x_list = list(x_tup)xl = x.tolist()x_list[1] = xl + [0.0, 0.0, 0.0, 0.0]y_list = list(y_tup)yl = y.tolist()y_list[1] = yl + [0.0, 0.0, 0.0, 0.0]x_i = si.splev(ipl_t, x_list) # x interpolate valuesy_i = si.splev(ipl_t, y_list) # y interpolate values
使用
x和值
y，您可以使用以下方法移动鼠标光标
ActionChains：
from selenium import webdriverfrom selenium.webdriver.common.action_chains import ActionChainsurl = "https://prepen.io/falldowngoboone/pen/PwzPYv"driver = webdriver.Chrome(executable_path="/home/selenium/chromedriver2.25")driver.get(url)action = ActionChains(driver);startElement = driver.find_element_by_id('drawer')# First, go to your start point or Element:action.move_to_element(startElement);action.perform();for mouse_x, mouse_y in zip(x_i, y_i): action.move_by_offset(mouse_x,mouse_y); action.perform(); print(mouse_x, mouse_y)
