输入年月日,输出是这年的第多少天.
#include "stdio.h"
void main()
{
int year,month,day,sum;
printf("请输入年月日:");
scanf("%d%d%d",&year,&month,&day);
switch(month)
{
case 1:sum=day;break;
case 2:sum=31+day;break;
case 3:sum=31+28+day;break;
case 4:sum=31+28+31+day;break;
case 5:sum=31+28+31+30+day;break;
case 6:sum=31+28+31+30+31+day;break;
case 7:sum=31+28+31+30+31+30+day;break;
case 8:sum=31+28+31+30+31+30+31+day;break;
case 9:sum=31+28+31+30+31+30+31+31+day;break;
case 10:sum=31+28+31+30+31+30+31+31+30+day;break;
case 11:sum=31+28+31+30+31+30+31+31+30+31+day;break;
case 12:sum=31+28+31+30+31+30+31+31+30+31+30+day;break;
default:printf("输入错误n");
}
if((year%4==0&&year%100!=0||year%400==0)&&month>=2)
sum++;
printf("这是这一年的第%d天n",sum);
}
输出九九乘法表
#include "stdio.h"
void main()
{
int i,j,k;
for(i=1;i<10;i++)
{
for(j=1;j<=i;j++)
{
k=i*j;
printf("%d*%d=%-3d",i,j,k);
}
printf("n");
}
}



