力扣 495. 提莫攻击 C++

判断下一次中毒时间是否在持续时间内即可，如果在就只累加时间差timeSeries[i + 1] - timeSeries[i]，否则就累加duration
for循环在len-1时结束即可，因为最后一次中毒一定会累加duration的时间，
所以最后返回sum + duration

int findPoisonedDuration(vector& timeSeries, int duration) {
	int sum = 0;
	int len = timeSeries.size();
	for (int i = 0; i < len-1; ++i)
	{
		if (timeSeries[i + 1] - timeSeries[i] > duration)
			sum += duration;
		else
			sum += timeSeries[i + 1] - timeSeries[i];
	}
	return sum + duration;
}