事实证明，答案比我想的要简单得多-
我提供的链接之一实际上导致了该功能的更为详细的版本：
这能够处理我给它的任何范围。
但是，谢谢您的帮助：
为了后代而复制的代码：
## {{{ http://pre.activestate.com/recipes/578019/ (r15)#!/usr/bin/env python"""Bytes-to-human / human-to-bytes converter.based on: http://goo.gl/kTQMsWorking with Python 2.x and 3.x.Author: Giampaolo Rodola' <g.rodola [AT] gmail [DOT] com>License: MIT"""# see: http://goo.gl/kTQMsSYMBOLS = { 'customary' : ('B', 'K', 'M', 'G', 'T', 'P', 'E', 'Z', 'Y'), 'customary_ext' : ('byte', 'kilo', 'mega', 'giga', 'tera', 'peta', 'exa', 'zetta', 'iotta'), 'iec': ('Bi', 'Ki', 'Mi', 'Gi', 'Ti', 'Pi', 'Ei', 'Zi', 'Yi'), 'iec_ext' : ('byte', 'kibi', 'mebi', 'gibi', 'tebi', 'pebi', 'exbi', 'zebi', 'yobi'),}def bytes2human(n, format='%(value).1f %(symbol)s', symbols='customary'): """ Convert n bytes into a human readable string based on format. symbols can be either "customary", "customary_ext", "iec" or "iec_ext", see: http://goo.gl/kTQMs >>> bytes2human(0) '0.0 B' >>> bytes2human(0.9) '0.0 B' >>> bytes2human(1) '1.0 B' >>> bytes2human(1.9) '1.0 B' >>> bytes2human(1024) '1.0 K' >>> bytes2human(1048576) '1.0 M' >>> bytes2human(1099511627776127398123789121) '909.5 Y' >>> bytes2human(9856, symbols="customary") '9.6 K' >>> bytes2human(9856, symbols="customary_ext") '9.6 kilo' >>> bytes2human(9856, symbols="iec") '9.6 Ki' >>> bytes2human(9856, symbols="iec_ext") '9.6 kibi' >>> bytes2human(10000, "%(value).1f %(symbol)s/sec") '9.8 K/sec' >>> # precision can be adjusted by playing with %f operator >>> bytes2human(10000, format="%(value).5f %(symbol)s") '9.76562 K' """ n = int(n) if n < 0: raise ValueError("n < 0") symbols = SYMBOLS[symbols] prefix = {} for i, s in enumerate(symbols[1:]): prefix[s] = 1 << (i+1)*10 for symbol in reversed(symbols[1:]): if n >= prefix[symbol]: value = float(n) / prefix[symbol] return format % locals() return format % dict(symbol=symbols[0], value=n)def human2bytes(s): """ Attempts to guess the string format based on default symbols set and return the corresponding bytes as an integer. When unable to recognize the format ValueError is raised. >>> human2bytes('0 B') 0 >>> human2bytes('1 K') 1024 >>> human2bytes('1 M') 1048576 >>> human2bytes('1 Gi') 1073741824 >>> human2bytes('1 tera') 1099511627776 >>> human2bytes('0.5kilo') 512 >>> human2bytes('0.1 byte') 0 >>> human2bytes('1 k') # k is an alias for K 1024 >>> human2bytes('12 foo') Traceback (most recent call last): ... ValueError: can't interpret '12 foo' """ init = s num = "" while s and s[0:1].isdigit() or s[0:1] == '.': num += s[0] s = s[1:] num = float(num) letter = s.strip() for name, sset in SYMBOLS.items(): if letter in sset: break else: if letter == 'k': # treat 'k' as an alias for 'K' as per: http://goo.gl/kTQMs sset = SYMBOLS['customary'] letter = letter.upper() else: raise ValueError("can't interpret %r" % init) prefix = {sset[0]:1} for i, s in enumerate(sset[1:]): prefix[s] = 1 << (i+1)*10 return int(num * prefix[letter])if __name__ == "__main__": import doctest doctest.testmod()## end of http://pre.activestate.com/recipes/578019/ }}}
