numpy：数组中唯一值的最有效频率计数

看一下

np.bincount

http://docs.scipy.org/doc/numpy/reference/generated/numpy.bincount.html

import numpy as npx = np.array([1,1,1,2,2,2,5,25,1,1])y = np.bincount(x)ii = np.nonzero(y)[0]

接着：

zip(ii,y[ii]) # [(1, 5), (2, 3), (5, 1), (25, 1)]

要么：

np.vstack((ii,y[ii])).T# array([[ 1,  5],         [ 2,  3],         [ 5,  1],         [25,  1]])

或者您想将计数和唯一值结合起来。