itertools.groupby是一种方法（通常是这样）：
>>> l = ["data","more data","","data 2","more data 2","danger","","date3","lll"]>>> from itertools import groupby>>> groupby(l, lambda x: x == "")<itertools.groupby object at 0x9ce06bc>>>> [list(group) for k, group in groupby(l, lambda x: x == "") if not k][['data', 'more data'], ['data 2', 'more data 2', 'danger'], ['date3', 'lll']]
由于这种特殊情况，我们甚至可以作弊：
>>> [list(group) for k, group in groupby(l, bool) if k][['data', 'more data'], ['data 2', 'more data 2', 'danger'], ['date3', 'lll']]
