当响应代码304和200时出现Volley异常错误

Miguel-仅在成功响应后才调用此方法吗？

对于所有状态代码<200或状态代码> 200，Volley调用parseNetworkError（VolleyError
volleyError）而不是parseNetworkResponse（NetworkResponse response）方法。看这里 -

https://android.googlesource.com/platform/frameworks/volley/+/master/src/com/android/volley/toolbox/BasicNetwork.java

行号-118-120

  if (statusCode < 200 || statusCode > 299) {     throw new IOException();   }

和相应的捕获块行号-128 -151

catch (IOException e) { int statusCode = 0; NetworkResponse networkResponse = null; if (httpResponse != null) {     statusCode = httpResponse.getStatusLine().getStatusCode(); } else {     throw new NoConnectionError(e); } VolleyLog.e("Unexpected response pre %d for %s", statusCode, request.getUrl()); if (responseContents != null) {     networkResponse = new NetworkResponse(statusCode, responseContents,  responseHeaders, false);     if (statusCode == HttpStatus.SC_UNAUTHORIZED ||  statusCode == HttpStatus.SC_FORBIDDEN) {         attemptRetryonException("auth",      request, new AuthFailureError(networkResponse));     } else {         // TODO: only throw ServerError for 5xx status pres.         throw new ServerError(networkResponse);     } } else {     throw new NetworkError(networkResponse); }        }

如果要覆盖此行为，可以在BasicNetwork.java-> performRequest方法内添加特定于状态码的实现。

编辑：所以它不是因为状态码而是因为响应为空。好吧，我认为您在实现自定义Request类方面做得正确。Volley随附了一些预定义的流行请求类型，以简化易用性，但您始终可以创建自己的请求。与其基于状态码的实现，不如直接反序列化之前检查以下字符串是否为空-

String jsonString = new String(response.data,     HttpHeaderParser.parseCharset(response.headers));if (!jsonString .isEmpty()) {      return Response.success(new JSonObject(jsonString),     HttpHeaderParser.parseCacheHeaders(response));}else {return Response.success(new JSonObject(),         HttpHeaderParser.parseCacheHeaders(response));}

**尚未测试过，但您明白了:)