由于您的原始json包含一个只有一个元素的数组，因此PowerShell会将其压缩为仅一个元素。如果在输出中希望再次将其作为数组，请使用rokumaru的好答案。
但是，PowerShell
ConvertTo-Json不会生成格式精美的json，为此，我前段时间编写了一个辅助函数：
function Format-Json { <# .SYNOPSIS Prettifies JSON output. .DEscriptION Reformats a JSON string so the output looks better than what ConvertTo-Json outputs. .PARAMETER Json Required: [string] The JSON text to prettify. .PARAMETER Minify Optional: Returns the json string compressed. .PARAMETER Indentation Optional: The number of spaces (1..1024) to use for indentation. Defaults to 4. .PARAMETER AsArray Optional: If set, the output will be in the form of a string array, otherwise a single string is output. .EXAMPLE $json | ConvertTo-Json | Format-Json -Indentation 2 #> [CmdletBinding(DefaultParameterSetName = 'Prettify')] Param( [Parameter(Mandatory = $true, Position = 0, ValueFromPipeline = $true)] [string]$Json, [Parameter(ParameterSetName = 'Minify')] [switch]$Minify, [Parameter(ParameterSetName = 'Prettify')] [ValidateRange(1, 1024)] [int]$Indentation = 4, [Parameter(ParameterSetName = 'Prettify')] [switch]$AsArray ) if ($PSCmdlet.ParameterSetName -eq 'Minify') { return ($Json | ConvertFrom-Json) | ConvertTo-Json -Depth 100 -Compress } # If the input JSON text has been created with ConvertTo-Json -Compress # then we first need to reconvert it without compression if ($Json -notmatch 'r?n') { $Json = ($Json | ConvertFrom-Json) | ConvertTo-Json -Depth 100 } $indent = 0 $regexUnlessQuoted = '(?=([^"]*"[^"]*")*[^"]*$)' $result = $Json -split 'r?n' | ForEach-Object { # If the line contains a ] or } character, # we need to decrement the indentation level unless it is inside quotes. if ($_ -match "[}]]$regexUnlessQuoted") { $indent = [Math]::Max($indent - $Indentation, 0) } # Replace all colon-space combinations by ": " unless it is inside quotes. $line = (' ' * $indent) + ($_.TrimStart() -replace ":s+$regexUnlessQuoted", ': ') # If the line contains a [ or { character, # we need to increment the indentation level unless it is inside quotes. if ($_ -match "[{[]$regexUnlessQuoted") { $indent += $Indentation } $line } if ($AsArray) { return $result } return $result -Join [Environment]::newline}像这样使用它：
$json = Get-Content 'D:scripttest.json' -Encoding UTF8 | ConvertFrom-Json$json.yura.ContentManager.branch = 'test'# recreate the object as array, and use the -Depth parameter (your json needs 3 minimum)ConvertTo-Json @($json) -Depth 3 | Format-Json | Set-Content "D:scripttest1.json" -Encoding UTF8# instead of using '@($json)' you can of course also recreate the array by adding the square brackets manually:# '[{0}{1}{0}]' -f [Environment]::newline, ($json | ConvertTo-Json -Depth 3) | # Format-Json | Set-Content "D:scripttest1.json" -Encoding UTF8
