本文实例为大家分享了C++实现并查集的具体代码,供大家参考,具体内容如下
#include#include #include using namespace std; class UnionFind{ private: vector parent; int count; //优化,记录p和q所在组的深度,在合并时将深度小的结点的根指向深度大的结点的根 vector rank; public: UnionFind(int count){ parent.resize(count); rank.resize(count); this->count = count; for(int i = 0; i < count; ++i){ parent[i] = i; rank[i] = 1; } } ~UnionFind(){ parent.clear(); rank.clear(); } //路径压缩 int find(int p){ assert(p >= 0 && p < count); if(p != parent[p]) parent[p] = find(parent[p]); return parent[p]; } bool isConnected(int p, int q){ return find(p) == find(q); } void unionElement(int p, int q){ int pRoot = find(p), qRoot = find(q); if(pRoot == qRoot) return; if(rank[pRoot] < rank[qRoot]) parent[pRoot] = qRoot; else if(rank[qRoot] < rank[pRoot]) parent[qRoot] = pRoot; else{ //两者的rank相等 parent[pRoot] = qRoot; rank[qRoot] += 1; } } };
小编再补充一段代码,之前收藏的一段代码:
#includeusing namespace std; class UF { //cnt is the number of disjoint sets. //id is an array that records distinct identity of each set,when two sets are merged ,their id will be same. //sz is an array that records the child number of each set including the set self. int *id, cnt, *sz; public: // Create an empty union find data structure with N isolated sets. UF(int N) { cnt = N; id = new int[N]; sz = new int[N]; for (int i = 0; i 同时谢谢这位作者的分享
以上就是本文的全部内容,希望对大家的学习有所帮助,也希望大家多多支持考高分网。



