您必须绑定并触发
[type=file]元素上的change事件，并将文件名读取为：
$('#file-upload').change(function() { var i = $(this).prev('label').clone(); var file = $('#file-upload')[0].files[0].name; $(this).prev('label').text(file);});.custom-file-upload { border: 1px solid #ccc; display: inline-block; padding: 6px 12px; cursor: pointer;}<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script><form> <label for="file-upload" > <i ></i> Upload Image </label> <input id="file-upload" name='upload_cont_img' type="file" ></form>
