栏目分类:
子分类:
返回
名师互学网用户登录
快速导航关闭
当前搜索
当前分类
子分类
实用工具
热门搜索
名师互学网 > IT > 面试经验 > 面试问答

以XML显示层次结构

面试问答 更新时间: 发布时间: IT归档 最新发布 模块sitemap 名妆网 法律咨询 聚返吧 英语巴士网 伯小乐 网商动力

以XML显示层次结构

如果您模拟

level
connect by
下列,则可以使用DBMS_XMLGEN.newcontextfromhierarchy和CTE完成此操作:

SELECt DBMS_XMLGEN.getXML(DBMS_XMLGEN.newcontextfromhierarchy('with employee as (  select 1 id, ''A'' name, 2 managerid from dual union all  select 2 id, ''B'' name, 4 managerid from dual union all  select 3 id, ''C'' name, 4 managerid from dual union all  select 4 id, ''D'' name, null managerid from dual ), t1(lvl,id,name,managerid) AS (  -- Anchor member.  SELECt 1 as lvl,         id,          name,         managerid  FROM   employee    WHERe  managerid IS NULL  UNIOn ALL  -- Recursive member.  SELECt t1.lvl+1 as lvl,          t2.id,          t2.name,         t2.managerid  FROM   employee t2, t1  WHERe  t2.managerid = t1.id)SEARCH DEPTH FIRST BY id SET order1SELECt lvl, xmlelement("Node", xmlattributes(name AS "name", id AS "id"))FROM   t1ORDER BY order1')) FROM dual

输出

<?xml version="1.0"?><Node name="D" id="4">  <Node name="B" id="2">    <Node name="A" id="1"/>  </Node>  <Node name="C" id="3"/></Node>


转载请注明:文章转载自 www.mshxw.com
本文地址:https://www.mshxw.com/it/612211.html
我们一直用心在做
关于我们 文章归档 网站地图 联系我们

版权所有 (c)2021-2022 MSHXW.COM

ICP备案号:晋ICP备2021003244-6号