以下是我的简单解决方案，可使您达到80％的精度，非常适合我的目的。它仅适用于Arial，并且假定使用12 pt字体，但也可能与其他字体成比例。
def getApproximateArialStringWidth(st): size = 0 # in milinches for s in st: if s in 'lij|' ': size += 37 elif s in '![]fI.,:;/\t': size += 50 elif s in '`-(){}r"': size += 60 elif s in '*^zcsJkvxy': size += 85 elif s in 'aebdhnopqug#$L+<>=?_~FZT' + string.digits: size += 95 elif s in 'BSPEAKVXY&UwNRCHD': size += 112 elif s in 'QGOMm%W@': size += 135 else: size += 50 return size * 6 / 1000.0 # Convert to picas如果要截断字符串，则为：
def truncateToApproximateArialWidth(st, width): size = 0 # 1000 = 1 inch width = width * 1000 / 6 # Convert from picas to miliinches for i, s in enumerate(st): if s in 'lij|' ': size += 37 elif s in '![]fI.,:;/\t': size += 50 elif s in '`-(){}r"': size += 60 elif s in '*^zcsJkvxy': size += 85 elif s in 'aebdhnopqug#$L+<>=?_~FZT' + string.digits: size += 95 elif s in 'BSPEAKVXY&UwNRCHD': size += 112 elif s in 'QGOMm%W@': size += 135 else: size += 50 if size >= width: return st[:i+1] return st然后是以下内容：
>> width = 15>> print truncateToApproxArialWidth("the quick brown fox jumps over the lazy dog", width) the quick brown fox jumps over the>> print truncateToApproxArialWidth("THE QUICK BROWN FOX JUMPS OVER THE LAZY DOG", width) THE QUICK BROWN FOX JUMPS呈现时，这些字符串的宽度大致相同：
快速的棕色狐狸跳过了
快速棕狐跳
