没错，这与描述符协议有关。描述符是如何在Python中实现将接收器对象作为方法的第一个参数传递的方式。您可以从此处阅读有关Python属性查找的更多详细信息。下面以较低的级别显示了执行A.func =
func;时发生的情况；A.func：
# A.func = funcA.__dict__['func'] = func # This just sets the attribute# A.func# The __getattribute__ method of a type object calls the __get__ method with# None as the first parameter and the type as the second.A.__dict__['func'].__get__(None, A) # The __get__ method of a function object # returns an unbound method object if the # first parameter is None.a = A()# a.func()# The __getattribute__ method of object finds an attribute on the type object# and calls the __get__ method of it with the instance as its first parameter.a.__class__.__dict__['func'].__get__(a, a.__class__)# This returns a bound method object that is actually just a proxy for# inserting the object as the first parameter to the function call.
因此，是在类或实例上查找该函数，将其转换为方法，而不是将其分配给类属性。
classmethod并且
staticmethod只是略有不同的描述符，类方法返回绑定到类型对象的绑定方法对象，而静态方法仅返回原始函数。
