每次找到与上一个字符不同的字符，则表示运行（连续重复的字母）结束，因此您应记下当前运行的长度（即的值
count），然后重置计数。最后，您可以打印最大值。
char[] array = S.toCharArray()int count = 1;int max = 0;char maxChar = 0;for(int i=1; i<array.length; i++){ // Start from 1 since we want to compare it with the char in index 0 if(array[i]==array[i-1]){ count++; } else { if(count>max){ // Record current run length, is it the maximum? max=count; maxChar=array[i-1]; } count = 1; // Reset the count }}if(count>max){ max=count; // This is to account for the last run maxChar=array[array.length-1];}System.out.println("Longest run: "+max+", for the character "+maxChar); // Print the maximum.
