更改ASP MVC3中使用的默认JSON序列化程序

最好的选择是从JsonResult类继承并覆盖Execute方法，例如

public class CustomJsonResult: JsonResult{    public CustomJsonResult()    {       JsonRequestBehavior = JsonRequestBehavior.DenyGet;    }    public override void ExecuteResult(ControllerContext context) { if (context == null) {     throw new ArgumentNullException("context"); } if (JsonRequestBehavior == JsonRequestBehavior.DenyGet &&     String.Equals(context.HttpContext.Request.HttpMethod, "GET", StringComparison.OrdinalIgnoreCase)) {     throw new InvalidOperationException(MvcResources.JsonRequest_GetNotAllowed); } HttpResponsebase response = context.HttpContext.Response; if (!String.IsNullOrEmpty(ContentType)) {     response.ContentType = ContentType; } else {     response.ContentType = "application/json"; } if (ContentEncoding != null) {     response.ContentEncoding = ContentEncoding; } if (Data != null) {     CustomJsSerializer serializer = new CustomJsSerializer();     response.Write(serializer.Serialize(Data)); }        }}

代码来自mvc3的JsonResult类，并更改了此行

JavascriptSerializer serializer = new JavascriptSerializer();

至

CustomJsSerializer serializer = new CustomJsSerializer();

您可以在操作方法中使用此类，例如

public JsonResult result(){    var model = GetModel();    return new CustomJsonResult{Data = model};}

另外，您可以在base控制器中覆盖Controller类的json方法，例如

public class baseController:Controller{   protected internal override JsonResult Json(object data)        { return new CustomJsonResult { Data = data };        }}

现在，如果您拥有baseController中的所有控制器，

returnJson(data)

Json