您的JSON对象不正确,因为它具有多个具有相同名称的属性。您应该返回“学生”对象的数组。
[ { "id": 456, "full_name": "GOOBER ANGELA", "user_id": "2733245678", "stin": "2733212346" }, { "id": 123, "full_name": "BOB, STEVE", "user_id": "abc213", "stin": "9040923411" }]然后,您可以如此迭代:
for (var i = 0, len = objJSON.length; i < len; ++i) { var student = objJSON[i]; $("<div id="" + student.id + "">" + student.full_name + " (" + student.user_id + " - " + student.stin + ")</div>")... }


