P5730 【深基5.例10】显示屏

液晶屏上，每个阿拉伯数字都是可以显示成 3×5 的点阵的（其中 X 表示亮点，. 表示暗点）。现在给出数字位数（不超过 100）和一串数字，要求输出这些数字在显示屏上的效果。数字的显示方式如同样例输出，注意每个数字之间都有一列间隔。

无

无

输入 #1复制

10
0123456789

输出 #1复制

XXX...X.XXX.XXX.X.X.XXX.XXX.XXX.XXX.XXX
X.X...X...X...X.X.X.X...X.....X.X.X.X.X
X.X...X.XXX.XXX.XXX.XXX.XXX...X.XXX.XXX
X.X...X.X.....X...X...X.X.X...X.X.X...X
XXX...X.XXX.XXX...X.XXX.XXX...X.XXX.XXX

注意每个数字之间都有一列间隔。

AC代码：

#include 
#include 
using namespace std;

int main()
{
	int n;
	cin >> n;
	string s, ans[5]; //五个数组ans[1-5]分别记录一个数字的五个行的构成情况
	cin >> s;
	for (int i = 0; i < s.size(); i++)
	{
		if (s[i] == '0')
		{
			ans[0] += "XXX"; ans[4] += "XXX";
			ans[1] += "X.X"; ans[2] += "X.X"; ans[3] += "X.X";
		}
		if (s[i] == '1')
		{
			ans[0] += "..X"; ans[4] += "..X";
			ans[1] += "..X"; ans[2] += "..X"; ans[3] += "..X";
		}
		if (s[i] == '2')
		{
			ans[0] += "XXX"; ans[4] += "XXX";
			ans[1] += "..X"; ans[2] += "XXX"; ans[3] += "X..";
		}
		if (s[i] == '3')
		{
			ans[0] += "XXX"; ans[4] += "XXX";
			ans[1] += "..X"; ans[2] += "XXX"; ans[3] += "..X";
		}
		if (s[i] == '4')
		{
			ans[0] += "X.X"; ans[4] += "..X";
			ans[1] += "X.X"; ans[2] += "XXX"; ans[3] += "..X";
		}
		if (s[i] == '5')
		{
			ans[0] += "XXX"; ans[4] += "XXX";
			ans[1] += "X.."; ans[2] += "XXX"; ans[3] += "..X";
		}
		if (s[i] == '6')
		{
			ans[0] += "XXX"; ans[4] += "XXX";
			ans[1] += "X.."; ans[2] += "XXX"; ans[3] += "X.X";
		}
		if (s[i] == '7')
		{
			ans[0] += "XXX"; ans[4] += "..X";
			ans[1] += "..X"; ans[2] += "..X"; ans[3] += "..X";
		}
		if (s[i] == '8')
		{
			ans[0] += "XXX"; ans[4] += "XXX";
			ans[1] += "X.X"; ans[2] += "XXX"; ans[3] += "X.X";
		}
		if (s[i] == '9')
		{
			ans[0] += "XXX"; ans[4] += "XXX";
			ans[1] += "X.X"; ans[2] += "XXX"; ans[3] += "..X";
		}
		if (i != s.size() - 1) //最后一个数字不用空列
		{
			ans[0] += "."; ans[4] += ".";
			ans[1] += "."; ans[2] += "."; ans[3] += ".";
		}
	}
	cout << ans[0] << endl << ans[1] << endl << ans[2] << endl << ans[3] << endl << ans[4] << endl;//五行逐一输出
	return 0;
}

0

string用法详解：跳转见大佬