#include#include class Parent { public: virtual void Print() { std::cout << "Parent" << std::endl; } }; class Child : public Parent { public: void Print() override { std::cout << "Child" << std::endl; } }; template class A { public: A(ty t) : t_(t) {} void Print() { t_.Print(); } private: ty t_; }; int main() { std::shared_ptr> a = std::make_shared>(Child()); std::shared_ptr> b = std::reinterpret_pointer_cast>(a); std::cout << "a.use_count: " << a.use_count() << ", b.use_count: " << b.use_count() << std::endl; std::cout << "a address: " << a.get() << ", b address: " << b.get() << std::endl; b->Print(); getchar(); return 0; }
上图这种情况,常规的转换不能保证“转换以后,引用计数是正确的”。
用reinterpret_pointer_cast转换以后,可以保证这一点。



