我有以下几行：
d:ProjectsqqqDevelopmentqqq.MySol1.sln
d:ProjectsqqqqqqDevelopmentqqqMySol2.sln
d:ProjectsqqqDevelopmentMyInstaller.sln
d:ProjectsqqqqqqDevelopmentMyInstaller.sln
d:ProjectsDevelopmentMyInstaller.sln
我需要一个正则表达式，这将导致捕获：
Line 1: Development and MySol1.sln
Line 2: Development and MySol2.sln
Line 3: Development and MyInstaller.sln
Line 4: Development and MyInstaller.sln
Line 5: Development and MyInstaller.sln
因此，一个正则表达式，将删除（忽略）字qqq从行。 我一直在试图与调节，并有部分的解决方案：
复制代码 代码如下:
.*\(?.*)\.{3}(?.*)
这导致：
Line 1: Development and .MySol1.sln
Line 2: qqqDevelopment and MySol2.sln
Line 3: Development and nstaller.sln
Line 4: Development and nstaller.sln
Line 5: Development and nstaller.sln
因此，.{3}应固定
1.我认为，应该工作：
.*\(?:qqq)?(?.*)\(?:qqq)?(?.*)
