>>> import datetime>>> first_time = datetime.datetime.now()>>> later_time = datetime.datetime.now()>>> difference = later_time - first_time>>> seconds_in_day = 24 * 60 * 60datetime.timedelta(0, 8, 562000)>>> divmod(difference.days * seconds_in_day + difference.seconds, 60)(0, 8) # 0 minutes, 8 seconds
从第一次减去以后的时间将
difference = later_time - first_time创建一个仅保留时差的
datetime对象。在上面的示例中，它是0分钟，8秒和562000微秒。
