事实证明，这在JSch中是完全可能的，最困难的部分只是查找文档。我在下面使用的代码，希望其他人会有所帮助！（我知道，我知道需要进行优化。在其他地方也定义了变量，但是希望任何需要此变量的人都可以解决这些问题！）
public static String oldestFile() { Vector list = null; int currentOldestTime; int nextTime = 2140000000; //Made very big for future-proofing ChannelSftp.LsEntry lsEntry = null; SftpATTRS attrs = null; String nextName = null; try { list = Main.chanSftp.ls("*.xml"); if (list.isEmpty()) { fileFound = false; } else { lsEntry = (ChannelSftp.LsEntry) list.firstElement(); oldestFile = lsEntry.getFilename(); attrs = lsEntry.getAttrs(); currentOldestTime = attrs.getMTime(); for (Object sftpFile : list) { lsEntry = (ChannelSftp.LsEntry) sftpFile; nextName = lsEntry.getFilename(); attrs = lsEntry.getAttrs(); nextTime = attrs.getMTime(); if (nextTime < currentOldestTime) { oldestFile = nextName; currentOldestTime = nextTime; } } attrs = chanSftp.lstat(Main.oldestFile); long size1 = attrs.getSize(); System.out.println("-Ensuring file is not being written to (waiting 1 minute)"); Thread.sleep(60000); //Wait a minute to make sure the file size isn't changing attrs = chanSftp.lstat(Main.oldestFile); long size2 = attrs.getSize(); if (size1 == size2) { System.out.println("-It isn't."); fileFound = true; } else { System.out.println("-It is."); fileFound = false; } } } catch (Exception ex) {ex.printStackTrace();} return Main.oldestFile;}
