如何制作具有多个数组的JSON对象？

在最外层，JSON对象以a开头，以a

{

}

样本数据：

{    "cars": {        "Nissan": [ {"model":"Sentra", "doors":4}, {"model":"Maxima", "doors":4}, {"model":"Skyline", "doors":2}        ],        "Ford": [ {"model":"Taurus", "doors":4}, {"model":"Escort", "doors":4}        ]    }}

如果将JSON分配给名为data的变量，则对其进行访问将类似于以下内容：

data.cars['Nissan'][0].model   // Sentradata.cars['Nissan'][1].model   // Maximadata.cars['Nissan'][2].doors   // 2for (var make in data.cars) {    for (var i = 0; i < data.cars[make].length; i++) {        var model = data.cars[make][i].model;        var doors = data.cars[make][i].doors;        alert(make + ', ' + model + ', ' + doors);    }}

另一种方法（对汽车模型使用关联数组而不是索引数组）：

{    "cars": {        "Nissan": { "Sentra": {"doors":4, "transmission":"automatic"}, "Maxima": {"doors":4, "transmission":"automatic"}        },        "Ford": { "Taurus": {"doors":4, "transmission":"automatic"}, "Escort": {"doors":4, "transmission":"automatic"}        }    }}data.cars['Nissan']['Sentra'].doors   // 4data.cars['Nissan']['Maxima'].doors   // 4data.cars['Nissan']['Maxima'].transmission   // automaticfor (var make in data.cars) {    for (var model in data.cars[make]) {        var doors = data.cars[make][model].doors;        alert(make + ', ' + model + ', ' + doors);    }}

编辑：

校正：JSON对象开始于

{

}

[

]

此外，原始JSON数据中的重大语法错误也已得到纠正：JSON对象中的所有键名都必须用双引号引起来，并且JSON对象或JSON数组中的所有字符串值也必须用双引号引起来。

看到：

• JSON规范
• JSONLint-JSON验证器