JAVA（2021-11-22）leetcode每日一题---- 打乱数组

 洗牌算法，记录一下子

class Solution {

    private int[] arr;
    private int n;
    private int[] nums;
    Random random = new Random();

    public Solution(int[] nums) {
        
        this.arr = nums;
        this.nums = arr.clone();
        n = nums.length;
    }
    
    public int[] reset() {
        return arr;
    }
    
    public int[] shuffle() {
        for(int i=0;i 
for循环遍历，每个数和他后边的数换，就是等概率的了