没有内置功能可以为您做到这一点，您必须为其编写一个函数。
如果您 知道 字符串不包含任何正则表达式中特殊的字符，那么您可以作弊一点，如下所示：
if (new RegExp(substrings.join("|")).test(string)) { // At least one match}…这会创建一个正则表达式，该正则表达式是您要查找的子字符串（例如）的一系列 替换
，
one|two并测试是否有匹配的子字符串，但是如果任何子字符串包含任何特殊字符在正则表达式（
*，
[等）中，您必须先将其转义，最好只进行无聊的循环。
现场示例：
var substrings = ["one", "two", "three"];var str;// Setupconsole.log("Substrings: " + substrings.join(","));// Try it where we expect a matchstr = "this has one";if (new RegExp(substrings.join("|")).test(str)) { console.log("Match using '" + str + "'");} else { console.log("No match using '" + str + "'");}// Try it where we DON'T expect a matchstr = "this doesn't have any";if (new RegExp(substrings.join("|")).test(str)) { console.log("Match using '" + str + "'");} else { console.log("No match using '" + str + "'");}在对该问题的评论中，Martin询问了
Array.prototype.mapECMAscript5中的新方法。
map并没有太多帮助，但是
some：
if (substrings.some(function(v) { return str.indexOf(v) >= 0; })) { // There's at least one}现场示例：
var substrings = ["one", "two", "three"];var str;// Setupconsole.log("Substrings: " + substrings.join(","));// Try it where we expect a matchstr = "this has one";if (substrings.some(function(v) { return str.indexOf(v) >= 0; })) { console.log("Match using '" + str + "'");} else { console.log("No match using '" + str + "'");}// Try it where we DON'T expect a matchstr = "this doesn't have any";if (substrings.some(function(v) { return str.indexOf(v) >= 0; })) { console.log("Match using '" + str + "'");} else { console.log("No match using '" + str + "'");}尽管对polyfill来说是微不足道的，但您只能在符合ECMAscript5的实现中使用它。
2020年更新 ：
some带有箭头功能（ES2015 +）的示例可能更简单，您可以使用
includes而不是
indexOf：
if (substrings.some(v => str.includes(v))) { // There's at least one}现场示例：
const substrings = ["one", "two", "three"];let str;// Setupconsole.log("Substrings: " + substrings.join(","));// Try it where we expect a matchstr = "this has one";if (substrings.some(v => str.includes(v))) { console.log("Match using '" + str + "'");} else { console.log("No match using '" + str + "'");}// Try it where we DON'T expect a matchstr = "this doesn't have any";if (substrings.some(v => str.includes(v))) { console.log("Match using '" + str + "'");} else { console.log("No match using '" + str + "'");}甚至扔掉
bind它，尽管对我来说箭头功能更具可读性：
if (substrings.some(str.includes.bind(str))) { // There's at least one}现场示例：
const substrings = ["one", "two", "three"];let str;// Setupconsole.log("Substrings: " + substrings.join(","));// Try it where we expect a matchstr = "this has one";if (substrings.some(str.includes.bind(str))) { console.log("Match using '" + str + "'");} else { console.log("No match using '" + str + "'");}// Try it where we DON'T expect a matchstr = "this doesn't have any";if (substrings.some(str.includes.bind(str))) { console.log("Match using '" + str + "'");} else { console.log("No match using '" + str + "'");}
