杰克逊将字段序列化为其他名称

我不确定我是否能完全理解您的问题，但是据我所知，您可以执行类似的操作来实现不同的序列化。

创建一个自定义批注以保存所有可能的不同序列化选项：

@Target(ElementType.FIELD)@Retention(RetentionPolicy.RUNTIME)public @interface CustomJsonProperty {    String propertyName();    String format();    @Target(ElementType.FIELD)    @Retention(RetentionPolicy.RUNTIME)    @documented    @interface List {        CustomJsonProperty[] value();    }}

相应地注释您的班级：

@JsonSerialize(using = CustomJsonPropertySerializer.class)public class Bar {    @CustomJsonProperty.List({        @CustomJsonProperty(propertyName = "first-name", format = "A"),        @CustomJsonProperty(propertyName = "firstName", format = "B")    })    private String firstName;    @CustomJsonProperty.List({ @CustomJsonProperty(propertyName = "last-name", format = "A"), @CustomJsonProperty(propertyName = "lastName", format = "B")    })    private String lastName;    @CustomJsonProperty.List({ @CustomJsonProperty(propertyName = "gender-x", format = "A"), @CustomJsonProperty(propertyName = "gender", format = "B")    })    private String gender;    @JsonIgnore    private String format;    //getters & setters}

创建一个自定义序列化器来解释您的新注释：

public class CustomJsonPropertySerializer extends JsonSerializer<Bar> {    @Override    public void serialize(Bar bar, JsonGenerator jsonGenerator, SerializerProvider serializerProvider) throws IOException {        jsonGenerator.writeStartObject();        Field[] fields = bar.getClass().getDeclaredFields();        for (Field field : fields) { field.setAccessible(true); Object value = null; try {     value = field.get(bar); } catch (IllegalAccessException e) {     e.printStackTrace(); } if (field.isAnnotationPresent(CustomJsonProperty.List.class)) {     CustomJsonProperty[] properties = field.getAnnotation(CustomJsonProperty.List.class).value();     CustomJsonProperty chosenProperty = null;     for (CustomJsonProperty c : properties) {         if (c.format().equalsIgnoreCase(bar.getFormat())) {  chosenProperty = c;  break;         }     }     if (chosenProperty == null) {         //invalid format given, use first format then         chosenProperty = properties[0];     }     jsonGenerator.writeStringField(chosenProperty.propertyName(), value.toString()); }        }        jsonGenerator.writeEndObject();    }}

现在，您可以考虑属性名称的不同格式来序列化对象：

public static void main(String[] args) throws IOException {    Bar bar1 = new Bar("first", "last", "m", "A");    Bar bar2 = new Bar("first", "last", "m", "B");    ObjectMapper mapper = new ObjectMapper();    String json1 = mapper.writevalueAsString(bar1);    String json2 = mapper.writevalueAsString(bar2);    System.out.println(json1);    System.out.println(json2);}

输出：

{"first-name":"first","last-name":"last","gender-x":"m"}{"firstName":"first","lastName":"last","gender":"m"}

当然，上述序列化程序仅适用于Bar对象，但是可以通过

abstract StringgetFormat();

也许有比创建自己的东西更简单的方法，但是我不知道。让我知道是否有不清楚的地方，我可以再次详细说明。