如何在自己的线程中执行Web请求？

我建议您看一下ASyncTask类（自Android
1.5起可用）。

它简化了创建后台线程的过程，该后台线程在完成后便与GUI线程同步。

您应该能够使用代码列出的内容来实现您正在尝试的功能

private class DownloadFilesTask extends AsyncTask<String, List<Product>, Integer> {     protected List<Products> doInBackground(String... requestStrings) {        int count = requestStrings.length;        int results = 0;        for (int i = 0; i < count; i++) {          String requestString = requestStrings[i];          HttpGet httpGet = new HttpGet(requestString);          httpGet.addHeader("Accept", "text/xml");          String encodingString = "testuser:testpass";          String sEnpredString = base64Coder.enpreString(encodingString);          try{ String sContent = fetchURL(requestString, sEnpredString); XMLParser xmlParser = new XMLParser(); List <Product> products = xmlParser.getProducts(sContent); results++; publishProgress(products);          }          catch(Exception ex){ Log.e(TAG, ex.getMessage());          }        }        return results;     }     protected void onProgressUpdate(Integer... progress) {         // TODO You are on the GUI thread, and the first element in          // the progress parameter contains the last progress         // published from doInBackground, so update your GUI     }     protected void onPostExecute(int result) {       // Processing is complete, result contains the number of        // results you processed     } }

并通过调用执行

new DownloadFilesTask().execute(url1, url2, url3);