正则表达式匹配一个句子

这将做得很好。我对句子的定义：句子以非空格开头，以句点，感叹号或问号（或字符串结尾）结尾。标点符号后可能会有一个结束语。

[^.!?s][^.!?]*(?:[.!?](?!['"]?s|$)[^.!?]*)*[.!?]?['"]?(?=s|$)

import java.util.regex.*;public class TEST {    public static void main(String[] args) {        String subjectString =         "This is a sentence. " +        "So is "this"! And is "this?" " +        "This is 'stackoverflow.com!' " +        "Hello World";        String[] sentences = null;        Pattern re = Pattern.compile( "# Match a sentence ending in punctuation or EOS.n" + "[^.!?\s]    # First char is non-punct, non-wsn" + "[^.!?]*      # Greedily consume up to punctuation.n" + "(?:          # Group for unrolling the loop.n" + "  [.!?]      # (special) inner punctuation ok ifn" + "  (?!['"]?\s|$)  # not followed by ws or EOS.n" + "  [^.!?]*    # Greedily consume up to punctuation.n" + ")*# Zero or more (special normal*)n" + "[.!?]?       # Optional ending punctuation.n" + "['"]?       # Optional closing quote.n" + "(?=\s|$)",  Pattern.MULTILINE | Pattern.COMMENTS);        Matcher reMatcher = re.matcher(subjectString);        while (reMatcher.find()) { System.out.println(reMatcher.group());        }     }}

这是输出：

This is a sentence.

So is "this"!

And is "this?"

This is 'stackoverflow.com!'

Hello World

正确地匹配所有这些（最后一个句子没有结尾标点符号），看起来似乎并不那么容易！