WebClient上传带有POST值的UploadFile

没有内置功能可让您执行此操作。我已经在博客中发布了可以使用的扩展程序。以下是相关的类：

public class UploadFile{    public UploadFile()    {        ContentType = "application/octet-stream";    }    public string Name { get; set; }    public string Filename { get; set; }    public string ContentType { get; set; }    public Stream Stream { get; set; }}public byte[] UploadFiles(string address, IEnumerable<UploadFile> files, NamevalueCollection values){    var request = WebRequest.Create(address);    request.Method = "POST";    var boundary = "---------------------------" + DateTime.Now.Ticks.ToString("x", NumberFormatInfo.InvariantInfo);    request.ContentType = "multipart/form-data; boundary=" + boundary;    boundary = "--" + boundary;    using (var requestStream = request.GetRequestStream())    {        // Write the values        foreach (string name in values.Keys)        { var buffer = Encoding.ASCII.GetBytes(boundary + Environment.newline); requestStream.Write(buffer, 0, buffer.Length); buffer = Encoding.ASCII.GetBytes(string.Format("Content-Disposition: form-data; name="{0}"{1}{1}", name, Environment.newline)); requestStream.Write(buffer, 0, buffer.Length); buffer = Encoding.UTF8.GetBytes(values[name] + Environment.newline); requestStream.Write(buffer, 0, buffer.Length);        }        // Write the files        foreach (var file in files)        { var buffer = Encoding.ASCII.GetBytes(boundary + Environment.newline); requestStream.Write(buffer, 0, buffer.Length); buffer = Encoding.UTF8.GetBytes(string.Format("Content-Disposition: form-data; name="{0}"; filename="{1}"{2}", file.Name, file.Filename, Environment.newline)); requestStream.Write(buffer, 0, buffer.Length); buffer = Encoding.ASCII.GetBytes(string.Format("Content-Type: {0}{1}{1}", file.ContentType, Environment.newline)); requestStream.Write(buffer, 0, buffer.Length); file.Stream.CopyTo(requestStream); buffer = Encoding.ASCII.GetBytes(Environment.newline); requestStream.Write(buffer, 0, buffer.Length);        }        var boundaryBuffer = Encoding.ASCII.GetBytes(boundary + "--");        requestStream.Write(boundaryBuffer, 0, boundaryBuffer.Length);    }    using (var response = request.GetResponse())    using (var responseStream = response.GetResponseStream())    using (var stream = new MemoryStream())    {        responseStream.CopyTo(stream);        return stream.ToArray();    }}

现在您可以在应用程序中使用它：

using (var stream = File.Open(dumpPath, FileMode.Open)){    var files = new[]     {        new UploadFile        { Name = "file", Filename = Path.GetFileName(dumpPath), ContentType = "text/plain", Stream = stream        }    };    var values = new NamevalueCollection    {        { "client", "VIP" },        { "name", "John Doe" },    };    byte[] result = UploadFiles(address, files, values);}

现在，在你的PHP脚本，你可以使用

$_POST["client"]

$_POST["name"]

$_FILES["file"]