python dict排序

time_dict = {"year": "", "half_year": "", "month": "", "half_month": "", "week": "", "holiday": "", "day": "","mid_day": "", "hour": "", "minute": "", "second": ""}
dict_1={'year': '2019年', 'month': '02月', 'day': '17日', 'hour': '09时', 'minute': '30分'}
dict_2={'minute': '45分许'}

问题描述：
dict_1,dict_2, 想让dict_2继承dict_1中的元素

for k, v in time_dict.items():
    if k in dic_2:
        break
    else:
        if k in dic_1:
            dic_2[k] = dic_1[k]

问题描述：
让dict_2中的元素按照time_dict中元素的顺序排序

dict_2 = dict([(k, v) for d in map(lambda x: {x: dict_2[x]}, [r for r in time_dict.keys() if r in dict_2]) for k, v in d.items()])
print(dict_2)