SQL查询中Select的语法

这将为您提供A和B胜过C，D和E的所有游戏路线。

select * from games where gameid in        (select gameid from games        where name in ('Anna A', 'Barley B') and winloss=1         group by gameid         having count(*) = 2    intersect     select gameid from games        where name in ('Charly C', 'Dave D', 'Ed E') and winloss = 0         group by gameid         having count(*) = 3) ;

或者，您可以使用：

select *from games where gameid in (    select gameid from games where name = 'Anna A'   and winloss = 1   intersect    select gameid from games where name = 'Barley B' and winloss = 1   intersect     select gameid from games where name = 'Charly C'   and winloss = 0 intersect    select gameid from games where name = 'Dave D' and winloss = 0     intersect    select gameid from games where name = 'Ed E' and winloss = 0    ) ;

最适合您的。

然后

sum

group by