1
let a = [1, 2, 2, 1];let b = [2];let aSet = new Set(a);let bSet = new Set(b);let intersection = Array.from(new Set(a.filter(v => bSet.has(v))))console.log(intersection); // [2]
1
let a = [1, 2, 2, 1];let b = [2];let aSet = new Set(a);let bSet = new Set(b);let intersection = Array.from(new Set(a.filter(v => bSet.has(v))))console.log(intersection); // [2]
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