栏目分类:
子分类:
返回
名师互学网用户登录
快速导航关闭
当前搜索
当前分类
子分类
实用工具
热门搜索
名师互学网 > IT > 面试经验 > 面试问答

用户输入中不重复数字

面试问答 更新时间: 发布时间: IT归档 最新发布 模块sitemap 名妆网 法律咨询 聚返吧 英语巴士网 伯小乐 网商动力

用户输入中不重复数字

如下进行:

import java.util.Arrays;import java.util.Scanner;public class Main {    static int[] numbers = new int[6];    static Scanner keyboard = new Scanner(System.in);    public static void main(String args[]) {        // Test        choose();        System.out.println(Arrays.toString(numbers));    }    static void choose() {        int temp;        boolean valid;        for (int i = 0; i < 6; i++) { // Check if the integer is in the range of 1 to 59 do {     valid = true;     System.out.print("Enter in an integer (from 1 to 59): ");     temp = keyboard.nextInt();     if (temp < 1 || temp > 59) {         System.out.println("Error: Invalid integer.");         valid = false;     }     for (int j = 0; j < i; j++) {         if (numbers[j] == temp) {  System.out.println("Please enter a different number as you have already entered this");  valid = false;  break;         }     }     numbers[i] = temp; } while (!valid); // Loop back if the integer is not in the range of 1 to 100        }    }}

运行示例:

Enter in an integer (from 1 to 59): 100Error: Invalid integer.Enter in an integer (from 1 to 59): -1Error: Invalid integer.Enter in an integer (from 1 to 59): 20Enter in an integer (from 1 to 59): 0Error: Invalid integer.Enter in an integer (from 1 to 59): 4Enter in an integer (from 1 to 59): 5Enter in an integer (from 1 to 59): 20Please enter a different number as you have already entered thisEnter in an integer (from 1 to 59): 25Enter in an integer (from 1 to 59): 6Enter in an integer (from 1 to 59): 23[20, 4, 5, 25, 6, 23]


转载请注明:文章转载自 www.mshxw.com
本文地址:https://www.mshxw.com/it/516288.html
我们一直用心在做
关于我们 文章归档 网站地图 联系我们

版权所有 (c)2021-2022 MSHXW.COM

ICP备案号:晋ICP备2021003244-6号