如何动态添加XmlInclude属性

两种选择；最简单的（但给出奇数的xml）是：

XmlSerializer ser = new XmlSerializer(typeof(AList),    new Type[] {typeof(B), typeof(C)});

带有示例输出：

<AList xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">  <ListOfBs>    <B />    <B xsi:type="C" />  </ListOfBs></AList>

更为优雅的是：

XmlAttributeOverrides aor = new XmlAttributeOverrides();XmlAttributes listAttribs = new XmlAttributes();listAttribs.XmlElements.Add(new XmlElementAttribute("b", typeof(B)));listAttribs.XmlElements.Add(new XmlElementAttribute("c", typeof(C)));aor.Add(typeof(AList), "ListOfBs", listAttribs);XmlSerializer ser = new XmlSerializer(typeof(AList), aor);

带有示例输出：

<AList xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">  <b />  <c /></AList>

无论哪种情况，您都 必须 缓存并重新使用该

ser