本题要求实现一个函数,将两个字符串连接起来。
函数接口定义:
char *str_cat( char *s, char *t );
char *str_cat( char *s, char *t );
函数str_cat应将字符串t复制到字符串s的末端,并且返回字符串s的首地址。
裁判测试程序样例:
#include
#include
#define MAXS 10
char *str_cat( char *s, char *t );
int main()
{
char *p;
char str1[MAXS+MAXS] = {' '}, str2[MAXS] = {' '};
scanf("%s%s", str1, str2);
p = str_cat(str1, str2);
printf("%sn%sn", p, str1);
return 0;
}
输入样例:
abc
def
输出样例:
abcdef
abcdef
char *str_cat( char *s, char *t ){
int i,j;
for(i=strlen(s),j=0;t[j]!=' ';i++,j++){
s[i]=t[j];
}
return s;
}
#include
#include
#define MAXS 10
char *str_cat( char *s, char *t );
int main()
{
char *p;
char str1[MAXS+MAXS] = {' '}, str2[MAXS] = {' '};
scanf("%s%s", str1, str2);
p = str_cat(str1, str2);
printf("%sn%sn", p, str1);
return 0;
}
abc
def
输出样例:
abcdef
abcdef
char *str_cat( char *s, char *t ){
int i,j;
for(i=strlen(s),j=0;t[j]!=' ';i++,j++){
s[i]=t[j];
}
return s;
}
abcdef
abcdef



