public Stack<int> NumbersIn(int value){ if (value == 0) return new Stack<int>(); var numbers = NumbersIn(value / 10); numbers.Push(value % 10); return numbers;}var numbers = NumbersIn(987654321).ToArray();无需递归的替代方法:
public int[] NumbersIn(int value){ var numbers = new Stack<int>(); for(; value > 0; value /= 10) numbers.Push(value % 10); return numbers.ToArray();}


