您可以使用
public class Permutation
设计来解决您的问题。
请参阅此链接以供参考
要么
像这样 ：
private static Double calculatePermutationEntropy(List<Double> values, int baseOrder) { int valuesSize = values.size(); if (baseOrder >= valuesSize + 1) { throw new RuntimeException("The size of the values is bigger than the order"); } List<String> result = new ArrayList<String>(); // iterate over the input for (int i = 0; i < valuesSize - baseOrder + 1; i++) { List<Double> neightbors = values.subList(i, i + baseOrder); List<Double> orderedValues = new ArrayList<Double>(neightbors); String window = ""; for (int j = 0; j < neightbors.size(); j++) { // add the indexes in a string representation window += orderedValues.indexOf(neightbors.get(j)); } result.add(window); } // use the shannon entropy calculation to get the result return calculateShannonEntropy(result);}资源
