不,您只需要关闭最外面的流。它将一直委托给包装的流。
但是,您的代码包含一个概念上的失败,应该在中发生关闭
finally,否则当代码在打开和关闭之间引发异常时,它永远不会关闭。
例如
public static void main(String args[]) throws IOException { PrintStream ps = null; try { ps = new PrintStream(new FileOutputStream("myfile.txt")); ps.println("This data is written to a file:"); System.out.println("Write successfully"); } catch (IOException e) { System.err.println("Error in writing to file"); throw e; } finally { if (ps != null) ps.close(); }}(请注意,我更改了代码以 引发 异常,以便您了解问题的原因,该异常即包含有关问题原因的详细信息)
或者,当您已经在使用Java 7时,也可以使用ARM(自动资源管理;也称为try-with-
resources),这样您就不需要自己关闭任何东西:
public static void main(String args[]) throws IOException { try (PrintStream ps = new PrintStream(new FileOutputStream("myfile.txt"))) { ps.println("This data is written to a file:"); System.out.println("Write successfully"); } catch (IOException e) { System.err.println("Error in writing to file"); throw e; }}


