python算法—1234能组成不重复3位数

# -*- coding: UTF-8 -*-
'''
    @IDE    ：PyCharm
    @Author ：WangZheng
    @Date   ：2021/11/11 21:08
    @pagePath:
'''

def test(params):
    mlist = []
    count = 0
    for i in params:
        for j in params:
            for k in params:
                # 判断 三个值都不能相同
                if i!=j and j!=k and k!=i:
                    mlist.append(i+j+k)
                    count += 1
    print("一共有 {} 中情况，分别是 {}".format(count,mlist))

test("1234")

运行结果：

一共有 24 中情况，分别是 ['123', '124', '132', '134', '142', '143', '213', '214', '231', '234', '241', '243', '312', '314', '321', '324', '341', '342', '412', '413', '421', '423', '431', '432']