Python获取某年所有时间

import datetime

def all_days_in_a_year(year, time_format="%Y-%m-%d"):
    dt = datetime.timedelta(days=1)
    res = []
    start_date = datetime.datetime(year=year, month=1,day=1)
    now_year = datetime.datetime.now().year
    if year == now_year:
        end_date = datetime.datetime.now()
    elif year < now_year:
        end_date = datetime.datetime(year=year+1, month=1,day=1)
   else:
       return res
   while start_date < end_date:
       res.append(start_date.strftime(time_format))
       start_date += dt
   return res

# 调用
all_days_in_a_year(2021)

'''
['2021-01-01',
 '2021-01-02',
 '2021-01-03',
 '2021-01-04',
 '2021-01-05',
 '2021-01-06',
 ...
 '2021-11-03',
 '2021-11-04',
 '2021-11-05',
 '2021-11-06',
 '2021-11-07',
 '2021-11-08',
 '2021-11-09',
 '2021-11-10',
 '2021-11-11',
 '2021-11-12']
'''