栏目分类:
子分类:
返回
名师互学网用户登录
快速导航关闭
当前搜索
当前分类
子分类
实用工具
热门搜索
名师互学网 > IT > 面试经验 > 面试问答

Java如何提取完整的XML块

面试问答 更新时间: 发布时间: IT归档 最新发布 模块sitemap 名妆网 法律咨询 聚返吧 英语巴士网 伯小乐 网商动力

Java如何提取完整的XML块

添加到lwburk的解决方案中,要将DOM节点转换为字符串形式,可以使用Transformer:

private static String nodeToString(Node node)throws TransformerException{    StringWriter buf = new StringWriter();    Transformer xform = TransformerFactory.newInstance().newTransformer();    xform.setOutputProperty(OutputKeys.OMIT_XML_DECLARATION, "yes");    xform.transform(new DOMSource(node), new StreamResult(buf));    return(buf.toString());}

完整的例子:

public static void main(String... args)throws Exception{    String xml = "<A><B><id>0</id></B><B><id>1</id></B></A>";    documentBuilderFactory dbf = documentBuilderFactory.newInstance();    document doc = dbf.newdocumentBuilder().parse(new InputSource(new StringReader(xml)));    XPath xPath = XPathFactory.newInstance().newXPath();    Node result = (Node)xPath.evaluate("A/B[id = '1']", doc, XPathConstants.NODE);    System.out.println(nodeToString(result));}private static String nodeToString(Node node)throws TransformerException{    StringWriter buf = new StringWriter();    Transformer xform = TransformerFactory.newInstance().newTransformer();    xform.setOutputProperty(OutputKeys.OMIT_XML_DECLARATION, "yes");    xform.transform(new DOMSource(node), new StreamResult(buf));    return(buf.toString());}


转载请注明:文章转载自 www.mshxw.com
本文地址:https://www.mshxw.com/it/486948.html
我们一直用心在做
关于我们 文章归档 网站地图 联系我们

版权所有 (c)2021-2022 MSHXW.COM

ICP备案号:晋ICP备2021003244-6号