使用Json.Net解析JSON数组

您可以这样获得数据值：

string json = @"[     { ""General"" : ""At this time we do not have any frequent support requests."" },    { ""Support"" : ""For support inquires, please see our support page."" }]";JArray a = JArray.Parse(json);foreach (JObject o in a.Children<JObject>()){    foreach (JProperty p in o.Properties())    {        string name = p.Name;        string value = (string)p.Value;        Console.WriteLine(name + " -- " + value);    }}

小提琴：https :
//dotnetfiddle.net/uox4Vt